Question

2(root 2+root6)/3(root2+root3)​

Answer 1

$\huge \mathscr{\orange {\underline{\pink{\underline {Answer:-}}}}}$

√√[ 2(√2)+√6  ] / [  3√(2+√3)  ]

=[ √2 √(2+√3) ] /  [  3√(2+√3)  ]     [ take √2 common in the numerator]

=[  √2.√(2+√3)  ] / 3

= (2+ √6)/ 3

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