Question

2 + root 3/2- root 3​

Answer 1

your questions incomplete

Answer 2

Given to rationalise,

$\sf \frac{2 + \sqrt{3} }{2 - \sqrt{3} }$

$\sf = \frac{2 + \sqrt{3} }{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} }$

$\sf = \frac{ {(2 + \sqrt{3} )}^{2} }{ {(2)}^{2} - {( \sqrt{3}) }^{2} }$

$\sf = \frac{4 + 3 + 2 \sqrt{6} }{4 - 3}$

$\sf = 7 + 2 \sqrt{6}$

which is the required answer.