Math, asked by rajesh20199, 10 months ago

Internal cross sectional area of a pipe is 100 cm2. How much water can be contained in 10m length of the pipe.

Answers

Answered by Saby123
1

Cross Sectional area of the pipe = 100 cm ^ 2 = 10^-2 m sq

Length = 10 m.

Volm = 10 ^ -1 m cube = 100 litres.

Hope this helps you.

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Answered by amalkrishnanpd
0

Step-by-step explanation:

cross section area = 10cm2

length =10m = 1000cm

and = 10×1000 = 10000 cm3 = 10 litre

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