Question

2/ root3 -1 rationalise the denominater​

Answer 1

ANSWER:

$\frac{2}{ \sqrt{3} - 1 }$

$= \frac{2}{ \sqrt{3} - 1 } \times \frac{ \sqrt{3} + 1 }{ \sqrt{3} + 1}$

$= \frac{2( \sqrt{3} + 1) }{( \sqrt{3} - 1)( \sqrt{3} + 1) }$

$= \frac{2( \sqrt{3} + 1)}{( \sqrt{3})^{2} - {(1)}^{2} }$

$= \frac{2( \sqrt{3} + 1)}{3 - 1}$

$= \frac{2( \sqrt{3} + 1)}{2}$

$= \sqrt{3} + 1$

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