Math, asked by sandip19, 1 year ago

2(sec2 35°- cot 2 55°) - cos 28° cosec 62°/tan 18° tan36° tan 30° tan 54° tan 72°

Answers

Answered by MunuThapa
41
2{sec²35°-cot²(90°-35°)} - cos28° cosec (90°-28°) / tan18° tan36° tan30° tan(90°-36°) tan(90°-18°)
2{sec²35 - tan²35°} -cos28°sec28°/tan18°tan36°1/√3 tan36°tan18°
2×1 -1/ tan²18 tan²36 1/√3
2-1/tan²18 tan²(90-18°)1/√3
1/tan²18° cot²18°1/√3
1/1/√3
1×√3
√3Ans.

sandip19: thank you genius
MunuThapa: Your welcome, my friend
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