in an isosceles triangle the angle of top vertex is twice the sum of base angles find all exterior angles of triangle
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if it is an isosceles triangle the two base angles will be equal
let the base angle be a
the vertex angle will be 180-2a
according to the condition
2(a+a)=180-2a
2(2a)=180-2a
4a=180-2a
6a=180
a=30
so the base angles are 30 and the vertex angle is 120
so the exterior base angle is 330 degrees and the exterior vertex angle is 240 degrees
let the base angle be a
the vertex angle will be 180-2a
according to the condition
2(a+a)=180-2a
2(2a)=180-2a
4a=180-2a
6a=180
a=30
so the base angles are 30 and the vertex angle is 120
so the exterior base angle is 330 degrees and the exterior vertex angle is 240 degrees
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