2 SECA(Sec a -tan a)
/-2tan a (tan a- SEC A) = cosecA
pls answer fast
Answers
Answered by
1
Answer:
2secA(secA-tanA)/
2tanA(tanA-secA)
=2secA(1/cosA-sin/cosA)/2tanA(sinA/cosA-1/cosA)
=2secA(1-sin/cosA)/2tan(sinA-1/cosA)
=secA(1-sinA)/tan (sinA-1)
= 1/cosA(1-sinA)/sinA/cosA(sinA-1)
=1-sinA/sin²A-1
=1/sinA
=cosecA
= hence proved
please follow me and mark me as a brainlist answer
Similar questions