Math, asked by sandhu54, 10 months ago

2. Show that any positive odd integer is of the form 6q + 1, or 6q +.3, or 6q +5, where q is
some integer.

Answers

Answered by debika93
5

Answer:

hope it will help u mate :)

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Answered by MysteriousAryan
3

Answer:

Let 'a' be any positive integer and b=6

Apply Euclid division lemma to A and B

a = 6q + r \: \:  \:  \:  where \: 0   \leqslant r < 6

r=0,1,2,3,4,5

a=6q,6q+1,6q+2,6q+3,6q+4,6q+5

and. a is positive odd integer

a≠6q. or a≠ 6q+2 or a≠6q+4

And. a=6q+1 ,a=6q+3 , a=6q+5

Hence proved

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