Math, asked by animesh3557, 1 year ago

2 sin^2 30° tan 60° - 3( cos^260°/cos^2 30°) + cos^3 90° tan^2 0° + tan^7 45°

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Answered by Vaibhavhoax
22
 <b><i>solution !

= 2 \times (\frac{1}{2})^{2} \times \sqrt{3} - 3 \times \frac{ ({ \frac{1}{2} })^{2} }{ ({ \frac{ \sqrt{3} }{2} )}^{2} } + ({0})^{3} \times ({0})^{2} \\ + ({1})^{2} \\ \\ = 2 \times \frac{1}{4} \times \sqrt{3} - 3 \times \frac{ \frac{1}{4} }{ \frac{3}{4} } + 0 + 1 \\ \\ = 3 \times \frac{1}{4} \times \frac{4}{3} + 0 + 1 \\ \\ = \frac{ \sqrt{3} }{2} - 1 + 1 \\ \\ \implies \: \frac{ \sqrt{3} }{2}

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Answered by DheerajRao
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