Math, asked by shivani730, 1 year ago

2(sin^6+cos^6)-3(sin ^4+cos^4)+1=0

Answers

Answered by SidVK

If we convert sin^6¢ and sin^4¢ in the form of cos,

we finally get the equation =>

1 + 2cos^4¢ - 2cos^2¢ = 0

2cos^2¢ ( cos^2¢ - 1 ) = -1

Beacuse 2cos^2¢ = -1 is not possible.

So, cos^2¢ - 1 = -1

cos^2¢ = 0

cos¢ = 0

¢ = π/2.......●

Thus, the value of theta is π/2 or 90°.

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I apologize for my previous mistake but now I have corrected that mistake.

Hope it was helpful.

shivani730: sin^6Φ + cos ^6 Φ =1 how

SidVK: Sorry, there was some misunderstanding. But now I have answered right.

shivani730: pls answer step by step of 2(sin^6+cos^6)-3(sin^4+cos^4)=-1

SidVK: Sorry, I can't do all steps but I can only tell you the way to find this equation. See,.......Sin^6¢ = sin^2¢.sin^2¢.sin^2¢ = (1-cos^2¢)(1-cos^2¢)(1-cos^2¢)...when you calculate it put the value in the place of sin^6¢....do same operation with sin^4¢...and then you will get the equation which I have mentioNed in the answer.

shivani730: thanks

SidVK: Sorry, but my phone's camera is not working well. So, i can't elaborate. Hope above hint was helpful.

shivani730: ok

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