Question

2 sin square 30 degree minus 3 cos square 45 degree + tan square 60 degree + 3 sin square 90

Answer 1

i hope my ans. will help you....
thanku
please mark as brainlist...

Answer 2

Answer:

2$sin^2 30 - 3 cos^245 + tan^2 60 + 3 sin^2 90$ = 5.

Step-by-step explanation:

Explanation:

Given that, 2 sin square 30 degrees minus 3 cos square 45 degrees + tan square 60 degrees + 3 sin square 90.

This can be written as,

2$sin^2 30 - 3 cos^245 + tan^2 60 + 3 sin^2 90$

⇒ 2$(\frac{1}{2} )^2$ - 3 $(\frac{1}{\sqrt{2} })^2$ + $(\sqrt{3} )^2$ + 3(1)

{Where, $sin30 = \frac{1}{2}$ , $cos 45 = \frac{1}{\sqrt{2} }$ ,  and $sin 90 = 1$]

⇒ 2 × $\frac{1}{4}$ - 3 × $\frac{1}{2}$ + 3 + 3

⇒ $\frac{1}{2}$ - $\frac{3}{2}$ + 6

⇒  $\frac{1- 3 + 12}{2}$ = $\frac{10}{2}$ = 5

Final answer:

Hence, 5 is the required value of 2 sin square 30 degrees minus 3 cos square 45 degrees + tan square 60 degrees + 3 sin square 90.

#SPJ3