Question

2 sin squre A= sin squre 60 +sin square 45 then find sin A​

Answer 1

Answer:

hope it helps

Answer 2

(Г3/2)^2 + (1/Г2)^2 = 2 Sin2A
3/4 + 1/2 = 2 Sin2A
5/8 = Sin2A
SinA = sq root of 5/8