Question

2 sin theta-3 cos theta/4sin theta -9 cos theta if sec theta =13/5

Answer 1

2sinA-3cosA÷4sinA-9cosA

ifsecA=13/5

cosA=5/13

P=12

sinA=12/13
2sinA-3cosA÷4sinA-9cosA
2×12/13-3×5/13÷4×12/13-9×5/13
9/13÷3/13=3ans