2 sin theta minus one= 0 then prove that sec theta + tan theta=√3
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2sin theta = 1
sin thetha = 1/2
theta is 30
sec30 is 2/root3
tan30 = 1/root3
so 2/root3 + 1/root3 == root3
sin thetha = 1/2
theta is 30
sec30 is 2/root3
tan30 = 1/root3
so 2/root3 + 1/root3 == root3
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