Question

2 sin2 30 tan? 60 - 3 cos2 60 tan2 30​

Answer 1

Answer:

√3-2/2

Step-by-step explanation:

Evaluate the following : 2sin230°. tan60° – 3cos260°. sec230°

Evaluate the following : 2sin230°. tan60° – 3cos260°. sec230°We know that sin (30°) = 1/2 tan (60°) = √3 cos(60°) = 1/2 sec(30°) = 2/√3

Evaluate the following : 2sin230°. tan60° – 3cos260°. sec230°We know that sin (30°) = 1/2 tan (60°) = √3 cos(60°) = 1/2 sec(30°) = 2/√3

Evaluate the following : 2sin230°. tan60° – 3cos260°. sec230°We know that sin (30°) = 1/2 tan (60°) = √3 cos(60°) = 1/2 sec(30°) = 2/√3 =2×1/2)2×(√3)-(3×(1/2)2×(2/√3)2)

Evaluate the following : 2sin230°. tan60° – 3cos260°. sec230°We know that sin (30°) = 1/2 tan (60°) = √3 cos(60°) = 1/2 sec(30°) = 2/√3 =2×1/2)2×(√3)-(3×(1/2)2×(2/√3)2)=2×1/4×(√3)-(3×1/4×4/3)

Evaluate the following : 2sin230°. tan60° – 3cos260°. sec230°We know that sin (30°) = 1/2 tan (60°) = √3 cos(60°) = 1/2 sec(30°) = 2/√3 =2×1/2)2×(√3)-(3×(1/2)2×(2/√3)2)=2×1/4×(√3)-(3×1/4×4/3)=√3/2-1

Evaluate the following : 2sin230°. tan60° – 3cos260°. sec230°We know that sin (30°) = 1/2 tan (60°) = √3 cos(60°) = 1/2 sec(30°) = 2/√3 =2×1/2)2×(√3)-(3×(1/2)2×(2/√3)2)=2×1/4×(√3)-(3×1/4×4/3)=√3/2-1=√3-2/2

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