Question

2 Sin2 B- B cos2 B = 2 find ß В of ---​

Answer 1

Answer:

B=90°

Step-by-step explanation:

2sin^2 B - cos^2 B = 2

2sin^2B - 1 + sin^2 B = 2

3sin^2 B -1 = 2

3sin^2 B = 2 + 1

3sin^2 B = 3

sin^2 B = 3/3

sin^2 B = 1

so, B = 90°