2 sin²A = cos60 +sin²45 find sec²A
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Answered by
4
Answer:
2sin²A=cos60+sin²45
2sin²A=1/2+1/2
2sin²A=1
sin²A=1/2
sinA=1/√2
A=45°
sec²A=sec²45=(√2)²=2
Answered by
0
Answer:
2sin²A= cos60+sin²45
=1/2+1/2
= 1
sin² A. = 1/2
sinA. =1/√2
A. =45°
sec²A. = (√2)²=2
hope it helps!!!
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