Question

2
So the remainder obtained on dividing q(t) by 2t + 1 is 0.
Also, a
2
4
2.
+ 4
2
2
multiple
So, 21 + 1 is a factor of the given polynomial q(t), that is 9(1) is a
2t + 1.
EXERCISE 2.3
1. Find the remainder when x3 + 3x2 + 3x + 1 is divided by
sin p5+2
1
() x+1
(ii) x
(iii) x
(iv) x +
2
2. Find the remainder when x3 – ax2 + 6x – a is divided by x - a.
3. Check whether 7 + 3x is a factor of 3x3 + 7x.
4.5 Factorisation of Polynomials
Let us now look at the situation of Example 10 above more closely. It tells us that since
the remainder, a
0, (2t + 1) is a factor of q(t), i.e., q(t) = (2t + 1) g(t)
2​

Answer 1

yes it is a difficult question