Question

2. Solve for x: 16 × 4^x+2 - 16 × 2^x+1 + 1 = 0
A.X=1/3
B.X=4
D.X=5
E.X=-4
C.x= 1
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Answer 1

x-1) * (0.5)^(3-2x)=(1/8)^x

2^2(x-1) * 2^(-(3-2x)) = 2^-3x

2^(2x-2-3+2x) = 2^(-3x)

2^(4x-5)=2^(-3x)

4x-5=-3x

7x=5

x=5/7