Question

2. Solve the following equations and check the solution.
(a) -7 y = -28
(b) x/3 = -2
(c) y/4 = 7 (d) 8r/9 = 56
please give me correct answer if you give me correct answer I will make you brainliest ​

Answer 1

Answer:

(a) -7y = -28

y = -28/-7

y = 4

(b) x/3 = -2

x = -2 × 3

x = -6

(c) y/4 = 7

y = 7× 4

y = 28

(d) 8r/9 = 56

8r = 56 ×9= 504

r = 504/8

r= 63

Answer 2

$\Large{\underline{\underline{\mathfrak{ \bigstar \: Solution \: :}}}}$

• $\bf{(a) \: \: -7y \: = \: -28}$

ㅤㅤ➻ $\sf{-7y = -28}$

ㅤㅤ➻ $\sf{y = \Large{\cancel{\frac{-28}{-7}}} }$

ㅤㅤ➻ $\sf{y = 4}$

Hence, y = 4.

❐ Check :

⟼ -7y = -28

$\red\clubsuit$ Substituting y = 4, we get

$\tt{⟼ \: -7(4) = -28}$

$\tt{⟼ \: -28 = -28}$

Hence, LHS = RHS. ✔

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• $\bf{(b) \; \: \Large\frac{x}{3} \small \: = \: -2}$

ㅤㅤ➻ $\sf{ \Large\frac{x}{3} \small \: = \: -2}$

ㅤㅤ➻ $\sf{ x = (-2) × 3}$

ㅤㅤ➻ $\sf{ x = -6}$

Hence, x = -6.

❐ Check :

⟼ x/3 = -2

$\red\clubsuit$ Substituting x = -6, we get

$\tt{⟼ \: \Large\frac{-6}{3} \small \: = -2 }$

$\tt{⟼ \: -2 = -2}$

Hence, LHS = RHS. ✔

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• $\bf{ (c) \: \: \Large\frac{y}{4} \small \: = \: 7}$

ㅤㅤ➻ $\sf{ \Large\frac{y}{4} \small \: = \: 7}$

ㅤㅤ➻ $\sf{ y = 7 × 4}$

ㅤㅤ➻ $\sf{y = 28}$

Hence, y = 28.

❐ Check :

⟼ y/4 = 7

$\red\clubsuit$ Substituting y = 28, we get

$\tt{⟼ \: 28/4 = 7}$

$\tt{⟼ \: 7 = 7}$

Hence, LHS = RHS. ✔

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

• $\bf{ (d) \: \: \Large\frac{8r}{9} \small \: = \: 56}$

ㅤㅤ➻ $\sf{ \Large\frac{8r}{9} \small \: = \: 56}$

ㅤㅤ➻ $\sf{ 8r = 56 × 9 }$

ㅤㅤ➻ $\sf{ r = \Large\frac{56 \: × \: 9}{8} }$

ㅤㅤ➻ $\sf{ r = 63 }$

Hence, r = 63.

❐ Check :

⟼ 8r/9 = 56

$\red\clubsuit$ Substituting r = 63, we get

$\tt{⟼ \: \Large\frac{8 \: × \: 63}{9} \small \: = 56}$

$\tt{⟼ \: 8 × 7 = 56 }$

$\tt{⟼ \: 56 = 56 }$

Hence, LHS = RHS. ✔