Question

2.) Solve the following quadratic equations
6√3x²+7x=√3​

Answer 1

Plz mark as Brainliest and Thank for the superb Question

Answer 2

Step-by-step explanation:

$6 \sqrt{3} {x}^{2} + 7x = \sqrt{3} \\6 \sqrt{3} {x}^{2} + 7x - \sqrt{3} = 0 \\ 6 \sqrt{3} {x}^{2} + (9 - 2)x - \sqrt{3} = 0 \\ 6 \sqrt{3} {x}^{2} + 9x - 2x - \sqrt{3} = 0 \\ 6 \sqrt{3} {x}^{2} + 3 \sqrt{3} \sqrt{3 }x - 2x - \sqrt{3} = 0 \\ 3 \sqrt{3}x (2x + \sqrt{3} ) - 1(2x + \sqrt{3} ) = 0 \\ (2x + \sqrt{3} )(3 \sqrt{ 3 } x - 1) = 0 \\ if(2x + \sqrt{3} ) = 0 \\ x = - \frac{ \sqrt{3} }{2} \\ \\ if(3 \sqrt{3} x - 1) = 0 \\ 3 \sqrt{3} x = 1 \\ x = \frac{1}{3 \sqrt{3} }$