Question

2. solve the following simultaneously equation
(1) 3a+5b=26; a+5b=22
​ {Explane me Like a Sir and How To Solve please Help me }. And In This Seatution I Can't Aatend My Class So You Now

plz follow me then I follow you​

Answer 1

a=2 and b=4

Step-by-step explanation:

subtract the both equation

so you will get a=2

and then subtute a=2 in any equation there then you will get b=4

MAKE THIS ANSWER AS BRAINLIEST ANSWER

Answer 2

Answer:

a = 2

b = 4

Step-by-step explanation:

Given a pair of linear equations such that,

3a + 5b = 26

And

a + 5b = 22

To solve this pair.

Let's write these in standard form.

Therefore, we get,

=> 3a + 5b - 26 = 0 ........(1)

=> a + 5b - 22 = 0 ........(2)

Now, from eqn (2), we get,

=> a = 22-5b

Substituting this value in eqn (1), we get

=> 3(22-5b) + 5b - 26 = 0

=> 66 - 15b + 5b - 26 = 0

=> 15b-5b = 66-26

=> 10b = 40

=> b = 40/10

=> b = 4

Put this value, we get,

=> a = 22 - 5(4)

=> a = 22-20

=> a = 2

Hence, the values of a = 2 and b = 4.