2. solve the following simultaneously equation
(1) 3a+5b=26; a+5b=22
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Answers
Answered by
3
a=2 and b=4
Step-by-step explanation:
subtract the both equation
so you will get a=2
and then subtute a=2 in any equation there then you will get b=4
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Answered by
32
Answer:
a = 2
b = 4
Step-by-step explanation:
Given a pair of linear equations such that,
3a + 5b = 26
And
a + 5b = 22
To solve this pair.
Let's write these in standard form.
Therefore, we get,
=> 3a + 5b - 26 = 0 ........(1)
=> a + 5b - 22 = 0 ........(2)
Now, from eqn (2), we get,
=> a = 22-5b
Substituting this value in eqn (1), we get
=> 3(22-5b) + 5b - 26 = 0
=> 66 - 15b + 5b - 26 = 0
=> 15b-5b = 66-26
=> 10b = 40
=> b = 40/10
=> b = 4
Put this value, we get,
=> a = 22 - 5(4)
=> a = 22-20
=> a = 2
Hence, the values of a = 2 and b = 4.
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