Question

2. Solve : (x2 - x)2 +5 (x2 – x) + 4 = 0

Answer 1

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Solve : (x2 - x)2 +5 (x2 – x) + 4 = 0

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------>>>>Here is your answer<<<<--------

$➪(2x - x)2 + 5(2x - x) + 4 = 0$

$➪4x - 2x + 10x - 5x + 4 = 0$

$➪2x + 10x - 5x + 4 = 0$

$➪12x - 5x + 4 = 0$

$➪7x + 4 = 0$

$➪x = - \frac{4}{7}$

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Answer 2

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$(x2 - x)2 +5 (x2 – x) + 4 = 0</h2><h2>$

$= > (2x - x) \: 2 \: + 5 \: (2x - x) \: + 4 \: = 0$

$= > \: 2x \: + 10x \: - 5x \: + 4 \: = 0$

$7x \: + 4 \: = \: 0$

$x \: = \: \frac{ - 4}{7}$