Question

2 Solve x²p² - 2xyp + y² − x²y² − x² = 0.​

Answer 1

Given equation is :

x2p2 - 2xyp + 2y2 - x2 = 0

on solving we get p = ( 2xy + 2x(x2 - y2)1/2 )/2x2

,

sin-1 v = log x + log c or sin-1 v= -log x - log c

sin-1 y/x = ± log (cx) is the required solution

Answer 2

Answer: it’s a pleasure to help you friend..

Step-by-step explanation:

Given, x²p² - 2xyp + y² − x²y² − x²

x²p² - 2xyp + y² − x²y² − x² = $p^{2} x^{2}$ - $x^{2} y^{2}$ - 2pxy - $x^{2}$ + $y^{2}$

= 0

Hence proved..

Hope it’s useful friend..

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