Question

2. Take three glass bottles with wide mouths. Label them A, B and C. Fill
about half of bottle A with ordinary tap water. Fill bottle B with water
which has been boiled for several minutes, to the same level as in A. In
bottle C. take the same boiled water and of the same amount as in other
bottles. In each bottle put a few similar iron nails so that they are com-
pletely under water. Add a teaspoonful of cooking oil to the water in
bottle C so that it forms a film on its surface. Put the bottles away for a
few days. Take out nails from each bottle and observe them. Explain
your observations.​

Answer 1

Answer:

It is the experiment to show rusting of iron

Explanation:

bottle A: Iron nails will get rusted, because there is oxygen, moisture and water

bottle b: it will not get rusted because there is no oxygen in boiled water as boiling the water removes dissolved gases as well as oxygen

bottle c: it will also not get rusted because it is also boiled water and there is a layer of oil which prevents oxygen to do reaction

for the process of rusting moisture, water, and oxygen is required

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Answer 2

Answer: The nails in bottles B rust a little, nails in A are the most rusted and that in C remain unchanged.

For rusting both water and oxygen are necessary. Both the factors are present in the bottle A since oxygen is dissolved in water.

In bottle B, water is boiled and hence dissolved air is removed. Due to lack of oxygen, iron nails do not rust much.

In bottle C, the layer of oil present prevents dissolving of atmospheric air in the water and hence no rusting occurs