an object of height 6 centimetre is placed at the distance of 10 cm from a convex mirror with radius of curvature 30cm find the position and height of the image
Taniya7989:
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u=-10 and r=30cm
so f=r/2
f=30/2
f=15
using mirror formula
1/v + 1/u = 1/f
1/v + 1/(-10) = 1/15
1/v = 1/15+1/10
=(2+3)/30
=5/30
1/v=1/6
v=6cm
using magnification formula
h'/h = - v/u
h' = h(-v/u)
we have h= 6 and v=6 and u=-10
putting values
we get
=6(-6/-10)
=36/10
h=3.6cm
therefore image is formed virtual,erect and smaller in size
so f=r/2
f=30/2
f=15
using mirror formula
1/v + 1/u = 1/f
1/v + 1/(-10) = 1/15
1/v = 1/15+1/10
=(2+3)/30
=5/30
1/v=1/6
v=6cm
using magnification formula
h'/h = - v/u
h' = h(-v/u)
we have h= 6 and v=6 and u=-10
putting values
we get
=6(-6/-10)
=36/10
h=3.6cm
therefore image is formed virtual,erect and smaller in size
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