Question

2+tan 35°cot 55°cot 55°tan 35°-3sec 40°cosec 50°​

Answer 1

Step-by-step explanation:

(2+tan 35°/cot 55°) + (cot 55°/tan 35°)- 3 (sec 40°/cosec 50°)

= 2 {tan (90°-55°)/cot 55°} + {cot (90°-35°) /tan 35°} - 3 {sec (90°-50°)/cosec 50°}

= 2 (cot 55°/cot 55°) + (tan 35°/tan 35°) - 3 (cosec 50°/cosec 50°)

= 2 + 1 - 3

= 3 - 3

= 0 [REQUIRED ANSWER]

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