Question

2 tan square A + tan A - 6 factorize​

Answer 1

Answer:

x=-2or x=3÷2

let assume tanA=x

2x square+xtanA-6

2x square+4x-3x-6

2x(x+2)-3(x+2)

(2x-3)(x+2)

x=3÷2,x=-2

Answer 2

Solution →

$2 \: {tan \: }^{2} a \: + \: tan \: a - 6$

Assume that ,

• tan a = x

Now put 'x' in place of tan a -

$2 {x}^{2} + x - 6$

$2 {x}^{2} + 4x - 3x - 6$

$2x(x + 2) - 3(x + 2)$

$(2x - 3)(x + 2)$

$2x - 3 = 0 \\ 2x = 3 \\ x = \frac{3}{2}$

$x + 2 = 0 \\ x = - 2$

Now put the (tan a) in place of x

$</strong><strong> </strong><strong>tan \: a \: = \frac{3}{2}</strong><strong> </strong><strong>\</strong><strong>\</strong><strong> a = {tan}^{ - 1} ( \frac{3}{2} )</strong><strong>$

$x = - 2 \\ tan \: a = - 2 </strong><strong>\</strong><strong>\</strong><strong> a = {tan}^{ - 1} ( - 2)$

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