Question

2 tanA /1+tan^A = Sin 2A​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

The left member can be writtten in this way:

$(1) = 2 \sin(A) \cos(A)$

The right member can be written in this way:

$= > 2. \frac{ \frac{ \sin(A) }{ \cos(A) } }{1 + \frac{ {sin}^{2}(A)}{ {cos}^{2} (A)} }$

$= > \frac{ \frac{ \sin(A) }{ \cos(A) } }{ \frac{{ \cos }^{2}A + {sin}^{2}A}{ {cos}^{2}A } }$

$= 2. \frac{ \sin( A</p><p></p><p></p><p></p><p> ) }{ \cos(A</p><p></p><p>) </p><p></p><p>} . \frac{ {cos}^{2} A}{1} = \sin( {cos}^{2} A) \cos( {cos}^{2} A) = (1)</p><p></p><p>$