Question

2
${2}^{100}$
pleas give formula to solve​

Answer 1

Answer:

Answer: Value of 2100 = 1.2676506002 × 1030. 2100 = 1.2676506002 × 1030.

Step-by-step explanation:

Hope it helps you ✌️

Answer 2

Answer:

1.24*$10^{30}$

Solution:

There is a simple trick that can help to give the answer approximately. To calculate the exact value you will have to use a calculator.

Note: This trick does not give the exact value.

Trick:

Question 1:

If there is $2^a$ , divide the exponent in groups of $2^{10}$. The final term should be $2^x$ where x should be less than 10. If there is a third group having x less than 10 replace $2^x$ with the value of $2^x$.

Say, $2^{27}$ is given. Write it as $2^{10}$ * $2^{10}$ * $2^7$.

In our case,

$2^{100}$ = $2^{10}$ * $2^{10}$ * $2^{10}$ * $2^{10}$ * $2^{10}$ * $2^{10}$ * $2^{10}$ * $2^{10}$ * $2^{10}$ * $2^{10}$

Next, replace each $2^{10}$ with $10^3$.

So, our question becomes 1 * $10^{30}$

For every $10^3$ add 2.4%. We have used 10 times $10^{30}$ so we have to add 24% of 1 to 1 i.e. 1+(24% of 1) * $10^{30}$. If there was third group having $2^x$ (x less than 10 ) then we would have added 2.4% of $2^x$ for every $10^3$ to $2^x$

(1+0.24)*$10^{30}$

1.24 * $10^{30}$

Original answer is 1.26 * $10^{30}$ and our answer is 1.24 * $10^{30}$.

Question 2:

$2^{27}$

First divide the exponent in groups of $2^{10}$.

$2^{27}$ = $2^{10}$ * $2^{10}$ * $2^7$

Replace every $2^{10}$ with $10^3$ and $2^7$ with 128.

Our exponent becomes 128*$10^6$ or 1.28 * $10^8$.

Now we have to add ((2 * 2.4%) of 1.28) + 1.28 for every $10^3$.

2^27 = (1.28 + (4.8% *1.28)) *$10^8$

2^27 = (1.28 + 0.06144)*$10^8$

2^27 = 1.34144 * $10^8$

Original answer is 1.342 * $10^8$ and our answer is 1.341 * $10^8$.