Question

2. दिखाइए कि
(i) tan 48° tan 23° tan 42° tan 67° =1
(ii) cos 38°cos 52° -sin 38° sin 52° = 0​

Answer 1

Step-by-step explanation:

(i) L.H.S tan(90°- 42°) tan(90°- 67°) tan 42° tan67°

cot42° cot67° tan 42° tan67°

1/tan 42° cot67° tan42° 1/cot67° = 1

L.H.S= R.H.S

(ii) L.H.S cos(90°-52°) cos 52°- sin(90°-52°)sin52°

sin52° cos52°- cos52° sin52°

1/cos52° cos52° - 1/sin52° sin52°=0

L.H.S= R.H.S

Answer 2

Answer:

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