Question

(2) The amount after 3 years on a principal
of 64000 at the rate of compound
interest 12 5 p.c.p.a. is
​

Answer 1

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Given❇

Time = 3yrs

Rate = 12.5

Principal

Find❇

The amount after giving compound interest = ?

Solution❇

$= a = p( { \frac{r + 1}{100} })^{n} \\ = a = 64000( { \frac{12.5 + 100}{100} })^{3} \\ = a = 64000 ({ \frac{112.5}{100} })^{3} \\ =a = 8 \times 22.5 \times 22.5 \times 22.5$

= a = 91,125

For compound interest

= Amount - principal

= 91125 - 64000

= 27, 125

_________________________

Answer 2

The amount after 3 years on a principal of 64000 at the rate of compound interest 12.5 p.c.p.a. is Rs. 91125.

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Let's understand a few concepts:

To solve the given problem we will use the following formula for calculating the amount in C.I.:

$\bigstar\:\boxed{\bold{A = P\bigg [1 + \frac{R}{100} \bigg]^n}}\:\bigstar$

where A = amount, P = principal, R = rate of compound interest and n = no. of years.

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Let's solve the given problem:

The sum of money, i.e., Principal (P) = Rs. 64000

The rate of interest (R) = 12.5% p.a.

The no. of years (n) = 3 years

Therefore, by using the above formula of finding the amount in compound interest, we get

$A = 64000 \times\bigg [1 + \frac{12.5}{100} \bigg]^3}$

$\implies A = 64000 \times\bigg [ \frac{100 + 12.5}{100} \bigg]^3}$

$\implies A = 64000 \times\bigg [ \frac{1 12.5}{100} \bigg]^3}$

$\implies A = 64000 \times\bigg [ 1.125\bigg]^3}$

$\implies A = 64000 \times1.423828125$

$\implies \bold{A =Rs.\:91125}$

Thus, the amount after 3 years on a principal of 64000 at the rate of compound interest of 12.5 per cent per annum is Rs. 91,125.

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