Question

2. The angles of a triangle are in the ratio 3: 5:10. Find the measure of each angle of the
triangle.​

Answer 1

QuesTion:

The angles of a triangle are in the ratio 3:5:10. Find the measure of each angle of the triangle.

SoluTion :

The ratio given is 3:5:10

Let the unknown constant be g

==> 3g + 5g + 10g = 180° [Angle sum property]

==> 18g = 180°

==> g = 180°/18

==> g = 10°

Therefore, the measures are :

==> 3g = 3(10°) = 30°

==> 5g = 5(10°) = 50°

==> 10g = 10(10°) = 100°

VeriFication :

3g + 5g + 10g = 180° [Angle sum property]

3(10°) + 5(10°) + 10(10°) = 180°

30° + 50° + 100° = 180°

180° = 180°

Hence verified !!

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Answer 2

$\huge{\sf{\star{\underline{\underline{\pink{Solution:}}}}}}$

The ratio given is 3:5:10

Let the unknown constant be g

==> 3g + 5g + 10g = 180° [Angle sum property] =

==> 18g = 180°

==> g = 180/18

==D> g = 10°

Therefore, the measures are :

==> 3g = 3(10%) = 30°

==> 5g = 5(10%) = 50°

==> 10g = 10(10°) = 100° =

VeriFication:

3g + 5g + 10g = 180° Angle sum property]

3(10°) + 5(10°) + 10(10°) = 180°

30° + 50° + 100° = 180°

180° = 180°

Hence verified !