PQ us the diameter of a ciude and PR is a chord 4 00-240
PR= 30cm. find the distance of PR 120m the center
of the the end circle
and
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Circles drawn on the diameter as a focal distance of any point lying on the parabola x^2 - 4x + 6y + 10 = 0 will touch a fixed line whose equation is:
Missing: PQ ciude 00-240 30cm. 120m end
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REF.Image x^2 - 4x + 6y + 10 = 0 (x - 2)^2 = - 4. 32(y + 1) F≡ (2,( - 1 - 32)) [Focus] = (2, -52) C→ any point on the parabola = (h,k) Slope of FC ... More
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