Question

2. The coach of a cricket team buys 3 bats and 6 balls for 3900. Later, she buys
bat and 3 more balls of the same kind for? 1300, Represent this situation algebraically








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Answer 1

Answer:

let cost of bat be x and ball be y

3x + 6y =3900  --------1

x + 9y = 1300 (she buys 3 more so we plus 6 to 3) --------2

using subtitution it easily be solved

x=1300-9y  --------- 3

substitute the value of x in equation  (1) , we get

3(1300 -9y) +6y =3900

3900 - 21y  = 3900

Step-by-step explanation:

Answer 2

Answer:

it is start from

Let. rate of bat = xRs

and ball rate =yRs

and the rest answer is in the image

Step-by-step explanation:

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