Physics, asked by zarin933, 13 days ago

2. The decomposition of phosphine PH3 proceeds according to the following equation-4PH3(g) P4 (g) + 6H2(g) It is found that the reaction follows the following rate equation : Rate = k[PH3]The half life of PH3 is 37.9 sec at 120 0Ca) How much time is required for ¾ th of PH3 to decompose?b) What fraction of the original sample of PH3 remains behind after 1 min ?3. Explaina) Order of a reaction b) Molecularity of a reaction

Answers

Answered by tamojeet0404
0

Answer:

Mark as Brainlist

Explanation:

2. The decomposition of phosphine PH3 proceeds according to the following equation-4PH3(g) P4 (g) + 6H2(g) It is found that the reaction follows the following rate equation : Rate = k[PH3]The half life of PH3 is 37.9 sec at 120 0Ca) How much time is required for ¾ th of PH3 to decompose?b) What fraction of the original sample of PH3 remains behind after 1 min ?3. Explaina) Order of a reaction b) Molecularity of a reaction

Attachments:
Similar questions