the brakes applied to a car produce an acceleration of 4m/s2 in the opposite direction to the motion if the car takes 3s to stap after the applicate of brakes calculate the distance traveled during this time
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Answered by
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Answer:
18m
Explanation:
Initial velocity(u)=u
Final velocity(v)=0
Time(t)=3s
From 1st equation of motion, v=u+at
0=u+(-4×3)
u=12m/s
Then,From 2nd equation of motion,
s=ut+at2
s=12×3+1/2×-4×3×3
s=36+(-18)
s=36-18
s=18m
Therefore,Distance travelled during this time is 18m
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