Question

2. The diagonal of a rectangle field is (x + 8) meter and the sides are x meter and (x + 4) meter
find the value of x.​

Answer 1

Answer:

$we \: know \: that \: \\ {diagonal}^{2} = {lenght}^{2} + {breadth}^{2} \\ {(x + 8)}^{2} = {x}^{2} + {(x + 4)}^{2} \\ {x}^{2} + 16x + 64 = {x}^{2} + {x}^{2} + 8x + 16 \\ {x}^{2} + 16x + 64 = 2 {x}^{2} + 8x + 16 \\ 16x - 8x + 64 - 16 = 2 {x}^{2} - {x}^{2} \\ 8x + 48 = {x}^{2} \\ {x}^{2} - 8x - 48 = 0 \\ {x}^{2} - 12x + 8x - 48 = 0 \\ x(x - 12) + 8(x - 12) = 0 \\ (x - 12)(x + 8) = 0 \\ x = 12and \: x = - 8$