Question

2) The diagonals of a rhombus bisect each other of measures 8cm and 6cm.Find its perimeter.

Answer 1

Diagonals of rhombus bisect at 90 degree
So by using pythagoras theorem
H^2=6^2+8^2
H=10

Now H= side of rhombus

Similarly the lengths of other 3 sides will also be the same

Now add all 4 sides

Perimeter=40 cm

Answer 2

Answer:

20cm

Step-by-step explanation:

Perimeter=4a

perimeter = 4(

$\sqrt{8 \div 2 + 6 \div 2}$

Perimeter = 4 ×5

Perimeter = 20cm