Math, asked by yashbhosale54, 9 months ago

2. The diameter of a cylindrical roller 120 cm
long is 84 cm. It takes 500 revolution to level a
play- ground. Find the cost of levelling it at
Rs.7.50 per m2​

Answers

Answered by PeepingMoon
6

Answer:

surface area of on revolution = 2∏rh

= 2 x 22/ 7 x 60 x 84

now for 500 revolution = 2 x 22/7 x 60 x 84 x 500

=1584 m2

Cost per M2 = rs 7.50

1584 M2 = rs 11880

Step-by-step explanation:

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