2. The first term and c.d of an AP are -8 and 5 respectively. Which
term of an AP is 137?
Answers
Answered by
2
Answer:
137 is 30th term
Step-by-step explanation:
a=-8
d=5
an=137
n=?
an= a+(n-1)d
137 = -8+(n-1) 5
145=(n-1) 5
145/5=n-1
29=n-1
30=n
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Answered by
1
Answer:
30
Value of 30th term is 137.
Step-by-step explanation:
a1= -8
c.d=5
an=137
n=?
an=a+(n-1)d
137=-8+(n-1)5
145÷5=(n-1)
29=n-1
n=30
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