Question

2. The following numbers are obviously not perfect squares Give reuson
(1) 1057
(ii) 23453
(iii) 7928
(iv) 222222
(v) 64000
(vi) 89722
(vii) 222000
(vi) 505050​

Answer 1

Step-by-step explanation:

because unit digit of those numbers are 0,2,3,8,7 which can't be a perfect square.

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Answer 2

: Required Answer

➝ We know that natural numbers ending in the digits 0, 2, 3, 7 and 8 are not perfect squares.

i. 1057 ⟹ Ends with 7

ii. 23453 ⟹ Ends with 3

iii. 7928 ⟹ Ends with 8

iv. 222222 ⟹ Ends with 2

v. 64000 ⟹ Ends with 0

vi. 89722 ⟹ Ends with 2

vii. 222000 ⟹ Ends with 0

viii. 505050 ⟹ Ends with 0