2). The force per unit length is the unit of..
Answers
Answer:
Let a, b, c ∈ R
Addition :
( a ∗ b ) ∗ c
= ( a + b ) + c
= a + b + c
And
a ∗ ( b ∗ c )
= a ∗ ( b + c )
= a + b + c
Thus, a ∗ ( b ∗ c ) = ( a ∗ b ) ∗ c
Hence, it is associative.
Multiplication :
( a ∗b ) ∗ c
= ab ∗ c
= abc
And
a ∗ ( b ∗ c )
= a ∗ bc
= abc
Thus, ( a ∗ b ) ∗ c = a ∗ ( b ∗ c )
Hence, it is associative.
Substraction :
( a ∗ b ) ∗ c
= ( a - b ) ∗ c
= a - b - c
And
a ∗ ( b ∗ c )
= a ∗ ( b - c )
= a - b + c
Thus, ( a ∗ b ) ∗ c ≠ a ∗ ( b ∗ c )
Hence, it is not associative.
Division :
( a ∗ b ) ∗ c
= a/b ∗ c
= a/bc
And
a ∗ ( b ∗ c )
= a ∗ b/c
= ac/b
Thus, ( a ∗ b ) ∗ c ≠ a ∗ ( b ∗ c )
Hence, it is not associative
Hence Proved.
Explanation:
Since current in both the wire is flowing in same direction, so both wire will attract each other.
Force per unit length acting on the wire B due to A F=
2πr
μ
o
I
1
I
2
where r=1 cm=0.01 m
∴ F=
2π×0.01
4π×10
−7
×20×75
=0.03 N/m
Answer: