Find the coefficient of x in the expansion of (8x−9)^3. plss guys fast best will be marked as brainliest
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Answered by
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for integers the binomial expansion is
#(x+y)^n=x^n+^nC_1x^(n-1)y+^nC_2n^(n-2)y^2+....^nC_kx^(n-k)y^k+.....y^n#
where#" "^nC_k=(n!)/(k!(n-k)!)#
for #" "(x-3)^7#
the term including #" "x^5#
#" "^7C_2x^5(-3)^2#
#=(7!)/(2!(5!))xx9#
#=((7xx6xxcancel(5!))/(2xxcancel(5!)))xx9#
#=21xx9=189#
Answered by
1
Answer:
8 -9
Step-by-step explanation:
is it correct yes I know that
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