Question

2) The original volume of a liquid having expansion coefficient of 9.5 x 10-4 / ◦C was 4 litres. When heated it increased its volume by 190 ml. Calculate the rise in temperature of the liquid​

Answer 1

Answer:

really it is the correct solution of you question.

Explanation:

Given the value of coefficient of volume expansion of 5×10

−4

K

−1

As, original density of glycerine

ρ=ρ

0

(1+YΔT)

⇒ρ−ρ

0

=ρ

0

YΔT

Thus, fractional change in the density of glycerin for a rise of 40

0

C in its temperature.

ρ

0

ρ−ρ

0

=YΔT=5×10

−4

×40

200×10

−4

=0.020

.Hence,

option C is correct answer.