Question

2: The paint in a certain container is sufficient to paint an area equal to 9.375 sq.m. How many bricks of dimensions 22.5 cm x 10 cm x 7.5 cm can be painted out of this container?​

Answer 1

$\bold \red{Answer}$

Volume of paint = 9.375 m² = 93750 cm²

Dimension of brick = 22.5 cm×10 cm×7.5 cm²

Total surface area of a brick = 2(lb + bh + lh) cm²

= 2(22.5×10 + 10×7.5 + 22.5×7.5) cm²

= 2(225 + 75 + 168.75) cm²

= 2×468.75 cm2 = 937.5 cm²

Number of bricks can be painted = 93750/937.5 = 100

Answer 2

$\huge\red{Answer}</p><p>$

Given, Area to painted

$= 9.375 {m}^{2} \\ = 9.375 \times {(100)}^{2} \\ = 93750 {cm}^{2}$

Dimension of brick

$= 22.5cm \times 10cm \times 7.5cm$

Number of brick that can be painted out of the container = ( Area painted by the container)/(surface area of brick)

Total surface area of a brick

$= 2(lb + bh + lh) \: {cm}^{2}$

$= 2(225 + 75 + 168.75) {cm}^{2}$

$= 2 \times 468.75 {cm}^{2}$

$= 937.5 {cm}^{2}$

Therefore, number of bricks that can be painted

$= \frac{93750}{937.5} \\ = 100$

Hence, 100 bricks can be painted out of the container.