Question

the coach of a cricket team buys 7 bats and 6 balls for rupees 3800 later she buys 3 bats and 5 balls for rupees 1750 find the cost of each bat and each Ball​

Answer 1

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Let the cost of one Bat be x

and the cost of one ball be y

Then According to Question

7x+6y=3800 ---(i)

3x+5y=1750 ---(ii)

multiplying (i) by 3 and (ii) by 7 we get

21x+18y=11400 (iii)

21x+35y=12250 (iv)

subtracting (iv) from (iii) we get

−17y=−850

⇒y=50

putting y=50 in (i)

7x+6y=3800

⇒7x+6×50=3800

⇒7x=3800−300

⇒x=500

Therefore the cost of each bat is Rs 500

and the cost of each ball is Rs 50

Answer 2

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Let cost of each bat be ₹ 'x' &

Cost of each ball be ₹ 'y'.

According to the question:

7x + 6y = 3800-------(1)

3x + 5y = 1750 -------(2)

From equation --(1)

7x = 3800 - 6y

=> x = 3800 - 6y

7 ------- equation (3)

7 is equation ---(3)

Put equation (3) in equation (2):

$= > 3( \frac{3800 - 6y}{7} ) + 5y = 1750$

$= > \frac{11400 - 18y}{7} + 5y = 1750$

$= > \frac{11400 - 18y + 35y}{7} = 1750$

$= > 11400 + 17y = 12250$

$y = \frac{850}{17}$

$17y = 12250 - 11400$

$= > 17y = 850$

We get,

$y \: = 50$

Put y = 50 in equation ( 3 )

$x = \frac{3800 - 6 \times 50}{7}$

$x = \frac{3800 - 300}{7}$

$x = \frac{3500}{7}$

$x = 500$

So, The cost of each bat is ₹ 500 &

The cost of each ball is ₹ 50