2: The planet Jupiter has a mass 318 times that of the earth. Its radius is 11 times larger than that of the earth .find the acceleration due to gravity on the surface of the jupiter Me=6.0×10kg Re=6.4×10m
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Explanation:
Hence, M
J
=318 M
e
;R
J
=11.2 R
e
;V
e
=11.2 km/s
We know, V
J
=
R
J
2GM
J
and V
e
=
R
e
2GM
e
∴
V
e
V
J
=
M
e
M
J
×
R
J
R
e
⇒V
J
=V
e
M
e
M
J
×
R
J
R
e
V
J
=11.2{
M
e
(318 M
e
)
×
(11.2 R
e
)
R
e
}
2
1
=11.2(
11.2
318
)
2
1
=59.7 km/s.
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