Question

2. The point of the form (a, - a) always lies on the line
(A) x = a (B) ya-a (C) y = x (D) x+y=0
3. The graph of the linear equation 2x + 3y = 6 cuts the y-axis
(A) (2.0) (B) (0,3) (C) (3, 0) (D) (0, 2)
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Answer 1

Answer:

For the point of the form (a,−a) to lie on the line, its co ordinates should satisfy the equation,

A) For the line x=a,  

There is no y-coordinate, so it is 0

Since the point (a,−a) have y=−a, it does not lie on the line.

B) For the line y=a,  

There is no x-value, so x coordinate is 0

Since the point (a,−a) have x=a

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=0, it does not lie on the line.

C) For the line y=x,  

Both x and y co ordinates should be equal

Since, co ordinates of the point (a,−a) are not equal, it does not lie on the line.

D) For the line x+y=0  

Sum of x and y coordinates should be 0

Substituting co ordinates of the point (a,−a) in the equation x+y=0

We get a+(−a)=a−a=0

LHS = RHS

Hence, (a,−a) satisfies x+y=0.