Question

2. The population of a town is
a town is 1, 21,000. If it
increases annually at 10%.what will be its population 2 years hence ? What was it 2years ago​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Given: The population of a town is $121000$. It increases annually at $10\%$.

To find: We have to find the population of the town after $2$ years and $2$ years ago.

Solution:

The population of a town is $121000$.

It increases annually at $10\%$.

The population of the town after two years will be-

$=121000\times{\dfrac{110}{100}}\times{\dfrac{110}{100}}\\\\=146410$

The population of the town two years ago was-

$=121000\times{\dfrac{90}{100}}\times {\dfrac{90}{100}}\\=98010$

The population of the town after two years will be $146410$ and two years ago was $98010$.